Answer:
[tex]\Huge \boxed{\mathrm{13.5 \ Joules}}[/tex]
Explanation:
[tex]\sf Kinetic \ energy \ (J)=\frac{1}{2} \cdot mass \ (kg) \cdot (velocity \ (m/s)) ^2[/tex]
[tex]\mathrm{KE=\frac{1}{2} mv^2}[/tex]
The mass of the ball is 3 kg.
The velocity of the ball rolling is 3 m/s.
[tex]\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 3^2}[/tex]
Evaluating and solving for kinetic energy.
[tex]\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 9}[/tex]
[tex]\mathrm{KE=\frac{1}{2} \cdot 27}[/tex]
[tex]\mathrm{KE} =13.5[/tex]
The kinetic energy of the ball is 13.5 Joules.
