Answer:
The height of the object is 50 feet
Explanation:
Given that:
The path of an object projected at a 45 degree angle with initial velocity of 80 feet per second is given by the function [tex]h (x) =\dfrac{-32}{(80)^2}x^2+x[/tex]
where;
x is the horizontal distance traveled and h(x) is the height in feet.
The objective is to use the TRACE feature of your calculator to determine the height of the object when it has traveled 100 feet away horizontally.
Before then;
If the function [tex]h (x) =\dfrac{-32}{(80)^2}x^2+x[/tex]
and x = 100
then :
[tex]h (x) =\dfrac{-32}{(80)^2}(100)^2+100[/tex]
[tex]h (x) =\dfrac{-32}{6400} \times 10000+100[/tex]
[tex]h (x) =- 0.005 \times 10000+100[/tex]
[tex]h (x) =- 50+100[/tex]
h(x) = 50 feet
Using the TRACE CALCULATOR,
In your Trace calculator;
input Y = X - 32 X^2/(80) this because in the calculator Y denotes h(x)
Now over to the WINDOW
set the window as follows:
Xmin = 0
Xmax = 200
Xsc1 =1
Ymin = 0
Ymax = 50
Ysc = 1
Xres = 1
After that, click on the graph key and an output will display as seen in the image below.
Therefore, the show the value of Y which we earlier said it denotes the h(x) = 50 feet
