Plz plz plz someone help me with this

Answer:
a(n) = 3 . 11^(n-1)
Step-by-step explanation:
- Common ratio: r = a3 / a2 = 363 / 33 = 11
- The first term of that geometric sequence:
a1 = a2 / r = 33/11 = 3
- Formula for this sequence:
a(n) = a1 . r^ (n-1) = 3 . 11^(n-1)
--> Answer D