Answer:
The magnitude of the acceleration is 4.2 m/s²
Explanation:
Given;
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Acceleration = Δv / Δt
Δv is change in velocity
Δt is change in time
The magnitude of the acceleration of the powerful sports car during the motion is given by;
[tex]a = \frac{v-u}{t}\\\\a = \frac{25-0}{6}\\\\a = 4.2 \ m/s^2[/tex]
Therefore, the magnitude of the acceleration is 4.2 m/s²
The magnitude of the acceleration is 4.2 m/s²
Given that
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Now the magnitude should be
[tex]= (25 - 0) \div 6[/tex]
= 4.2 m/s²
Learn more: https://brainly.com/question/10283285?referrer=searchResults
