Respuesta :
Solution:-
Given that length of rectangle is 3 ft more than its breadth . Also , perimeter of rectangle is 62 ft . And we are asked to find the Length and breadth .
So , we know we can find perimeter of rectangle as :
[tex]\boxed{\red{\bf \dag Permiter_{rectangle}=2(l+b)}}[/tex]
Now , let us take the
- Breadth be x .
- Length be x + 3 .
So , as per Question :
[tex]\tt :\implies Perimeter=2(l+b)[/tex]
[tex]\tt :\implies 62 \cancel{ft.} = 2( x + 3 + x ) \cancel{ft.} [/tex]
[tex]\tt :\implies 62 = 2 ( 2x + 3 ) [/tex]
[tex]\tt :\implies 62 = 4x + 6 [/tex]
[tex]\tt :\implies 4x = 62 - 6 [/tex]
[tex]\tt :\implies4x = 56. [/tex]
[tex]\tt :\implies x =\dfrac{\cancel{56}}{\cancel{4}} [/tex]
[tex]\underline{\boxed{\red{\tt\longmapsto \:\:x\:\:=\:\:14}}}[/tex]
Hence we got x as 14 .
So , let's put the value in our assumption:
- [tex]\boxed{\green{\bf \pink{\dag} Length = x + 3 = 14 + 3 = 17 ft.}}[/tex]
- [tex]\boxed{\green{\bf \pink{\dag} Breadth = x = 14 ft.}}[/tex]
