The angle (3x - 10°) has a smaller value than the angle (6x+100), as 20 < 160; among the two supplementary angles.
Supplementary angles are those, which sum up to be = 180
Supplementary angle 1 + Supplementary angle 2 = 180
Given : Two supplementary angles are 3x - 10 , 6x + 100
So, (3x - 10) + (6x + 100) = 180
3x + 6x - 10 + 100 = 180
9x + 90 = 180
9 (x + 10) = 180
x + 10 = 180 / 9 = 20
x = 20 - 10 = 10
Hence, First angle ie 3x - 10 = 3 ( 10 ) - 10 = 20
Second angle ie 6x + 100 = 6 (10) + 100 = 160
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