Answer:
33.8.
Explanation:
Hello,
In this case, since the used equation is:
[tex]Q=mCp(T_2-T_1)[/tex]
Whereas the specific heat is 4.184 J/(g°C), we compute the mass as follows:
[tex]m=\frac{Q}{Cp(T_2-T_1)}[/tex]
Thus, the mass turns out:
[tex]m=\frac{3,710J}{4.184\frac{J}{g\°C} (48.9-22.7)\°C}\\\\m=33.8g[/tex]
And without units:
33.8.
Best regards.
