The equation of the line that passes through the points (-7, 21) and is parallel to the line y= 1/7x - 56 is 7y - x = 154
The standard equation of a line in point-slope form is expressed as:
[tex]y-y_0=m(x-x_0)[/tex]
m is the slope of the line
(x0, y0) is any point on the line
Given the equation y = 1/7 x - 56 parallel to this line, the slope of the line m = 1/7
Substitute the slope and the point into the formula to have:
[tex]y-21=\frac{1}{7} (x+7)\\7(y-21) = x+7\\7y - 147 = x+ 7\\7y-x = 154[/tex]
Hence the equation of the line that passes through the points (-7, 21) and is parallel to the line y= 1/7x - 56 is 7y - x = 154
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