Answer:
[tex]\rho =0.697\frac{lb}{in^3}[/tex]
Explanation:
Hello,
In this case, given that 1 inch equals 2.54 cm and 1 lb equals 453.6 g we apply the following conversion factor in order to compute the required density in lb/in³:
[tex]\rho=19.3\frac{g}{cm^3}*\frac{1lb}{453.6g} *(\frac{2.54cm}{1in} )^3\\\\\rho =0.697\frac{lb}{in^3}[/tex]
Best regards.
