Given :
A quadratic equation :
[tex]x^2+10x=15[/tex]
To Find :
The solution by completing the square method.
Solution :
[tex]x^2+10x=15\\\\x^2+2(1x)(5) + 5^2-5^2=15\\\\x^2+2(1x)(5)+25=40\\\\(x+5)^2=40\\\\x+5=\pm2\sqrt{10}\\\\x=2\sqrt{10}-5 \ ,\ x = -2\sqrt{10}-5[/tex]
Hence, this is the required solution.
