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Jamel has two identical cans. He lifts his foot in the air and slowly brings it down to put force on one of the metal cans. After Jamel lifts his foot back in the air, the metal can is bent in the middle. Jamel is going to use his foot in the same way to put force on the second metal can. What will most likely happen if Jamal moves his foot faster as he brings it down on the second metal can?
A. The second metal can will become shaped like the top of Jamal's foot.
B. The second metal can will become less bent than the first metal can.
C. The second metal can will become more bent than the first metal can.

Respuesta :

azikennamdi

Answer:

The correct answer is C) the second metal will become more bent than the first metal can.

Explanation:

There are two principles of physics at play here. The first is the Force applied versus the Work done.

Force is defined in physics as the mass of an object multiplied by the acceleration of the object.

[tex]F = M * A[/tex]

Work Done is define in physics as  Force x Displacement

In the question, we are not given the actual values of the Mass or the rate of acceleration of Jamal's leg.

We do know however that in the first case, he had slowly put his leg down on the can. That is, the rate of acceleration of his leg was lower that the rate of acceleration in the second. Mass (which in this case is the weight of his leg) remained constant.

The rate of accelaration of the object (which is his leg) was slow. Therefore the Work done relative to the second case was smaller.

With an increase in acceleration of the Mass in the second case, there is bound to be more work done.

Cheers!

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