Side of base of square, a = 10 km.
Height of pyramid , h = 12 km.
Volume of pyramid is given by :
[tex]V=\dfrac{a^2h}{3}\\\\V=\dfrac{10^2\times 12}{3}\ km^3\\\\V=400\ km^3[/tex]
Surface area is given by :
[tex]S.A=2ah + a^2\\\\S.A=(2 \times 10\times 12) + 10^2\ km^2\\\\S.A=340\ km^2[/tex]
Therefore, volume and surface area are 400 km³ and 340 km² respectively.
Hence, this is the required solution.
