Answer:
0.4455 mol H₂ and 0.1485 mol N₂
Explanation:
Given that,
Moles of ammonia = 0.297
We know that,
The balance equation is,
[tex]2NH_{3}\Rightarrow N_{2}+3H_{2}[/tex]
We need to calculate the mole of [tex]H_{2}[/tex]
Using given data
For H₂,
[tex]mole\ of\ H_{2}=0.297\ mol\ of\ NH_{3}\times\dfrac{3\ mol\ H_{2}}{2\ mol\ NH_{3}}[/tex]
[tex]mole\ of\ H_{2}=0.4455[/tex]
For N₂,
[tex]mole\ of\ N_{2}=0.297\ mol\ of\ NH_{3}\times\dfrac{1\ mol\ N_{2}}{2\ mol\ NH_{3}}[/tex]
[tex]mole\ of\ H_{2}=0.1485[/tex]
Hence, 0.4455 mol H₂ and 0.1485 mol N₂
