Answer:
Tension T in each rope will be 254.56 N.
Explanation:
From the picture attached,
Weight suspended by the two ropes will be supported by the vertical components of the tension in the ropes.
Vertical components of both the ropes = Tsin(45)° + Tsin(45)°
= 2Tsin(45)°
= [tex]2T(\frac{1}{\sqrt{2}})[/tex]
= [tex]T\sqrt{2}[/tex]
Since, [tex]T\sqrt{2}=360[/tex]
T = [tex]\frac{360}{\sqrt{2} }[/tex]
T = 254.56 N
Therefore, tension T in each rope will be 254.56 N.
