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A pitcher throws a ball to a batter, who hits the ball to the shortstop. If the ball travels in a straight line between each,
•What is the total distance traveled by the ball ? Round your answer to the nearest tenth of a foot.

Need Helpp A pitcher throws a ball to a batter who hits the ball to the shortstop If the ball travels in a straight line between each What is the total distance class=

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Answer:

Distance traveled by the ball will be 87.1 feet.

Step-by-step explanation:

Length of a segment between extreme ends [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Coordinates of batter and shortstop are (9, 9) and (45, 90) (in feet) respectively.

Batter hits the ball and the ball moves in a straight line.

Therefore, distance between batter and the shortstop will be,

d = [tex]\sqrt{(9-45)^2+(9-90)^2}[/tex]

  = [tex]\sqrt{(-36)^2+(-81)^2}[/tex]

  = [tex]\sqrt{1296+6561}[/tex]

  = [tex]\sqrt{7587}[/tex]

  = 87.10

  ≈ 87.1 feet

Therefore, distance traveled by the ball will be 87.1 feet.

The total distance traveled by the ball to the nearest tenth is 86.5 feet

If the ball travels in a straight line between each point, the total distance traveled by the ball will be gotten using the distance formula expressed as:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the coordinate of the pitcher and the batter and shortstop (9, 9) and (45, 90) respectively.

Substitute into the formula to have:

[tex]D=\sqrt{(90-9)^2+(45-9)^2}\\D=\sqrt{(81)^2+36^2}\\D = \sqrt{6561+1296} \\D=\sqrt{7857}\\D= 86.64feet[/tex]

Hence the total distance traveled by the ball to the nearest tenth is 86.5 feet

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