Answer:
The given expression does not define [tex]y[/tex] as a function of [tex]x.[/tex] (Answer: No)
Step-by-step explanation:
Let be [tex]x+9 = y^{2}[/tex], as we have understood from mathematical reading. This function indicates that [tex]y^{2}[/tex], not [tex]y[/tex] is a explicit function of [tex]x[/tex]. The correct form is obtained by increasing each side of the formula by [tex]\frac{1}{2}[/tex], that is to say:
[tex](x+9)^{\frac{1}{2} } = (y^{2})^{\frac{1}{2} }[/tex]
[tex]y = \pm \sqrt{x+9}[/tex]
Hence, the given expression does not define [tex]y[/tex] as a function of [tex]x.[/tex]
