Andrew walks along a road which can be modeled by the equation y=3x, where (0,0) represents his starting point. When he reaches the point (12,36), he turns right, so that he is traveling perpendicular to the original road, until he stops at a point which is due east of his starting point (in other words, on the x-axis).

What is the point where Andrew stops?

Respuesta :

Answer:

(120,0)

Steps:

y-36=-1/3(x-12)

(0)-36=-1/3(x-12)

(-3)(-36)=x-12

108=x-12

120=x

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The point where Andrew stops is (120,0).

What is the equation of a line?

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The slope of the perpendicular line will be,

m × 3 = -1

m = -1/3

Substitute the point in the line,

y = -(1/3)x + C

36 = -(1/3)12 + C

36 = -4 +C

C = 40

Now, the equation of the perpendicular line will be,

y = -(1/3)x + 40

The point will be due east, therefore, the value of y = 0,

0 =  -(1/3)x + 40

-40 = -(1/3)x

x = 120

Hence, the point where Andrew stops is (120,0).

Learn more about Equation of Line:

https://brainly.com/question/21511618

#SPJ2

Ver imagen ap8997154