Respuesta :
Similar shapes are shapes whose lengths are in equivalent ratio. [tex]\triangle ABC[/tex] and [tex]\triangle D E F[/tex] are similar because the side lengths of both triangles are in equivalent ratio (refer to attachment)
Step 1: Draw a random triangle [tex]\triangle ABC[/tex]
The lengths of two sides and an angle are:
[tex]AB=10[/tex]
[tex]BC=6[/tex]
[tex]\angle C = 90^o[/tex]
Step 2: Draw and measure the length of DE
[tex]DE = 15[/tex]
Step3 : Calculate the ratio
The corresponding line segment to DE is line segment AB.
So, the ratio (k) is:
[tex]k = \frac{DE}{AB}[/tex]
[tex]k = \frac{15}{10}[/tex]
[tex]k = 1.5[/tex]
Step 4: Multiply the ratio by the other line segment in step 1
In (1), we have:
[tex]BC=6[/tex]
So:
[tex]EF = k \times BC[/tex]
[tex]EF = 1.5 \times 6[/tex]
[tex]EF = 9[/tex]
Step 4: Draw a circle with center F and radius EF
The center of the circle is point F and the radius of the circle is 9 units
Step 5: Draw a ray from the center (i.e. point F) to DE
Refer to the attached image for
- Triangle ABC
- Triangle DEF
- Circle with center F and radius 9
- Ray from F to DE
Read more about angles, triangles and circles at:
https://brainly.com/question/11659907
