Respuesta :
Answer:
The answer is "10.84 g".
Explanation:
The formula for calculating the number for moles:
[tex]\text{Number of moles }= \frac{\ Mass}{ \ molar \ mass }[/tex]
In the given acid nitric:
Owing to the nitric acid mass = [tex]75.9 g[/tex]
Nitric acid molar weight[tex]= 63\ \frac{g}{mol}[/tex]
If they put values above the formula, they receive:
[tex]\text{moles in nitric acid} = \frac{75.9}{63}[/tex]
[tex]=1.204 \ mol[/tex]
In the given chemical equation:
[tex]3 NO_2 \ (g) + H_2O \ (l) \longroghtarrow 2 HNO_3 \ (aq) + NO\ (g)[/tex]
In this reaction, 2 mols of nitric acid are produced by 1 mole of water.
So, 1.204 moles of nitric acid will be produced:
[tex]= \frac{1}{2} \times 1.204[/tex]
[tex]=0.602\ \ \text{mol of water}.[/tex]
We are now using Equation 1 in determining the quantity of water:
Water moles [tex]= 0.602\ mol[/tex]
Water weight molar [tex]= 18.02 \ \frac{g}{mol}[/tex]
[tex]\to 0.602 = \frac{\text{mass of mols}}{ 18.02}\\\\\to \text{mass of mols} = 0.602 \times 18.02\\\\[/tex]
[tex]=10.84 \ g[/tex]
