Given:
Initial velocity,u = 0 m/s
Final velocity,v = 24 m/s
Distance covered,s = 56 m
To be calculated:-
Calculate the acceleration ( a ) .
Solution:-
According to the third equation of motion,
[tex] \bf \: {v}^{2} = {u}^{2} + 2as[/tex]
★ Substituting the values in the third equation of motion:
[tex] \sf \implies \: {(24)}^{2} = {(0)}^{2} + 2 \times a \times 56[/tex]
[tex] \sf \implies \: 576 = 112a[/tex]
[tex] \sf \implies \: a = \dfrac{576}{112} [/tex]
[tex] \sf\implies \: a = 5.14 \: m {s}^{ - 2} [/tex]
