Answer:
Vf = 0.68 m/s
Explanation:
First we find acceleration of the marble by using 2nd equation of motion:
s = Vi t + (1/2)at²
where,
s = distance covered = 140 cm = 1.4 m
t = time taken = 4.1 s
Vi = initial Velocity = 0 m/s (since, the marble was initially at rest)
a = acceleration = ?
Therefore,
1.4 m = (0 m/s)(4.1 s) + (1/2)(a)(4.1 s)²
a = (1.4 m)(2)/(4.1 s)²
a = 0.17 m/s²
Now, we use 1st equation of motion for final velocity (Vf)
Vf = Vi + at
Therefore,
Vf = 0 m/s + (0.17 m/s²)(4.1 s)
Vf = 0.68 m/s
