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Two identical conducting spheres, one that has an initial charge +Q, the other initially uncharged, are brought into contact. While the spheres are in contact, a positively charged rod is moved close to one sphere, causing a redistribution of the charges on the two spheres so the charge on the sphere closest to the rod has a charge of -Q. What is the charge of the other sphere?

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okpalawalter8

Answer:

The new charge is [tex]k = 2 Q[/tex]

Explanation:

From the question we are told that

The initial charge of the first one is [tex]+Q[/tex]

The charge on the sphere closest to the rod is [tex]-Q[/tex]

Generally at the point the charge was redistributed the charge on each sphere is [tex]+ \frac{Q}{2}[/tex]

Also from the question we are told that the new charge on one of the sphere is -Q

So this mean that

[tex]\frac{ Q}{2} + \frac{Q}{2} = -Q + k[/tex]

Here k is the charge on the other sphere

=>      [tex]k =  2 Q[/tex]

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