Answer:
effective rate of 6.59%
Explanation:
First, we solve for the amount after 2-years
[tex]2,000 \times (1 +\frac{0.06}{12}) ^{2 \times 12})+ 3,000 (1+\frac{0.07}{4})^4=[/tex]
[tex]Principal \: (1+ r)^{time} = Amount[/tex]
Principal 2,000.00
time 24.00
rate 0.00500
[tex]2000 \: (1+ 0.005)^{24} = Amount[/tex]
Amount 2,254.32
[tex]Principal \: (1+ r)^{time} = Amount[/tex]
Principal 3,000.00
time 4.00
rate 0.01750
[tex]3000 \: (1+ 0.0175)^{4} = Amount[/tex]
Amount 3,215.58
Total: 2,254.32 + 3,215.58 = 5,469.90
Now, we solve for the effective rate:
[tex]2,000(1+r_e)^2 + 3,000(1+r_e) - 5,469.90 = 0[/tex]
We use the quadratic formula and find the roots:
2.5658882124183746
1.0658882124183746
we use the positive one.
Getting an effective rae of 6.59%