The concentration of dye in Solution A is 23.5 M. A serial dilution is performed to make Solutions B and C. In the first dilution, 2 mL of Solution A is diluted with 12 mL water to make Solution B. Then, 9 mL of Solution B is then diluted with 1 mL of water to make Solution C. What is the concentration of dye in Solution C? Provide your response to three significant figures in units of molarity.

Respuesta :

Answer:

The concentration of dye in solution C is 3.02 M.

Explanation:

To find the concentration of dye in solution C we need to use the following equation:

[tex] V_{1}C_{1} = V_{2}C_{2} [/tex]

Where V is for volume and C is for concentration

In the first dilution we have:

[tex] V_{A}C_{A} = V_{T}C_{B} [/tex]

[tex] 2 mL*23.5 M = (2 mL + 12 mL)*C_{B} [/tex]                              

[tex] C_{B} = 3.36 M [/tex]

Now, in the second dilution:

[tex] V_{B}C_{B} = V_{T}C_{C} [/tex]

[tex] 9 mL*3.36 M = (9 mL + 1 mL)*C_{C} [/tex]  

[tex] C_{C} = 3.02 M [/tex]                        

Therefore, the concentration of dye in solution C is 3.02 M.

I hope it helps you!