Answer:
let the three numbers be x,y,z
X= z-6
Y= 4z
Z= z
Step-by-step explanation:
X+Y+Z=114
hence
=z-6+4z+z=114
=collect like times. X= 20-6=14
= z+4z+z=114+6. Y= 20*4=80
=6z=120. . Z= 20
z=20
Answer:
14 + 20 + 80 = 114
Step-by-step explanation:
Let's begin by representing our 1st number as x.
Then our 2nd number is said to be 6 more than the 1st number, which we can represent as x + 6.
Lastly, our 3rd number is said to be 4 times the 2nd number, which we can represent as 4(x + 6).
Now can write our equation to express the sum of these three numbers as 114 and then solve for x to find the values of these three numbers:
x + (x + 6) + 4(x + 6) = 114
x + x + 6 + 4x + 24 = 114
6x + 30 = 114
6x = 114 - 30
6x = 84
x = 84/6 = 14 (1st number)
x + 6 = 14 + 6 = 20 (2nd number)
4(x + 6) = 4(20) = 80 (3rd number)
We can check our answers by adding these numbers up to see if their sum is 114:
14 + 20 + 80 = 114
34 + 80 = 114
114 = 114
Their sum is 114, so we are confident that our three numbers are correct.
-Hope this helps
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