Write a system of inequalities to match the graph and prove that the coordinate point (-10, -14) is in the solution set

Answer:
y < x - 2
y ≥ 2x + 5
Step-by-step explanation:
For the equation of the dotted line,
Slope of the line = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Since the dotted lines passes through the points (-7, -9) and (2, 0)
Slope = [tex]\frac{-9-0}{-7-2}[/tex]
[tex]m_1[/tex] = 1
Therefore, equation of the line passing through (2, 0) and slope = 1 will be,
y - y' = m₁(x - x')
y - 0 = 1(x - 2)
y = x - 2
Since, shaded area is below the dotted line,
y < x - 2 will be the inequality.
Slope of the solid line passing through (-7, -9) and (0, 5) is,
[tex]m_2=\frac{-9-5}{-7-0}[/tex]
= 2
Therefore, equation of the line passing through (0, 5) and slope = 2 will be,
y - 5 = 2(x - 0)
y = 2x + 5
Since, the given line is a solid line and shaded area is above the line,
y ≥ 2x + 5 will be the inequality.
Since, (-10, -14) is lying in the common shaded area of both the inequalities, it will be the solution set of the graphed inequalities.