Answer:
2 m/s
Explanation: Given that a flatbed car of a train moves 8 m/s to the east. A jogger runs along to top the flatbed car (which is not very safe) with a velocity of 6 m/s to the west.
Since the jogger is moving in an opposite direction to the direction of the train, and velocity is the distance covered in a specific direction, the jogger will be moving at a velocity relative to the velocity of the train.
Velocity = (8 - 6) m/s
Velocity = 2 m/s
Therefore, the jogger will be moving at the speed of 2 m/s
