which equation shows P=2l + 2w when solved for w?
A. w= 2l/P
B. w= 2l-P/2
C. w=2l - p/2
D. w=p-2l/2

Solving for w by making w the subject of the formula, we would have: D. w = (P - 2l)/2.
To make a variable a subject of the formula, we solve for the variable.
Given the equation, P=2l + 2w, we are required to solve for w.
Thus:
P = 2l + 2w
Subtract both sides by 2l
P - 2l = 2w
Divide both sides by 2
(P - 2l)/2 = w
w = (P - 2l)/2
Therefore, solving for w by making w the subject of the formula, we would have: D. w = (P - 2l)/2.
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