Answer:
b
Step-by-step explanation:
we have the point
[tex](2,-4)[/tex]
so when
x=2
y=4
so we can try on all equations
[tex]y_1=2|x-2|-4\\\\y_1=2|2-2|-4\\\\y_1=2|0|-4\\\\y_1=0-4\\\\y_1=-4[/tex]
so equation 1 could be
[tex]y_2=\frac{1}{2} |x-2|-4\\\\y_2=\frac{1}{2}|2-2|-4\\\\y_2=\frac{1}{2}|0|-4\\\\y_2=0-4\\\\y_2=-4[/tex]
so equation 2 could be
[tex]y_3=2|x+2|-4\\\\y_3=2|2+2|-4\\\\y_3=2|4|-4\\\\y_3=8-4\\\\y_3=4[/tex]
so equation 3 is not
[tex]y_4=\frac{1}{2}|x+2|-4\\\\y_4=\frac{1}{2}|2+2|-4\\\\y_4=\frac{1}{2}|4|-4\\\\y_4=\frac{1}{2}(4)-4\\\\y_4=2-4\\\\y_4=-2[/tex]
so equation 4 is not
So another point that we have is
[tex](0,-3)[/tex]
so we plug in
[tex]y_1=2|x-2|-4\\\\y_1=2|0-2|-4\\\\y_1=2|-2|-4\\\\y_1=4-4\\\\y_1=0[/tex]
so this isn't
[tex]y_2=\frac{1}{2}|x-2|-4\\\\y_2=\frac{1}{2}|0-2|-4\\\\y_2=\frac{1}{2}|-2|-4\\\\y_2=\frac{1}{2}(2)-4\\\\y_2=1-4\\\\y_2=-3[/tex]
so the answer is b
