Answer:
The answer is "A device may include [tex]2 ^{56}[/tex]time more unique user IDs".
Explanation:
In the given question the total user ID access availability of 5 bits would also be [tex]2^{10}[/tex], and for user ID listings, its 12 bits should generate a maximum [tex]2^{66}[/tex] data allocation.
In this, it first calculate the value that is [tex]2^{(66-10)}=2^{56}[/tex] times, which was its amount of times most specific user IDs, that's why [tex]2 ^{56}[/tex] time is correct answer.
