Answer:
d = 8 m
Explanation:
Given that,
Initial speed, u = 0
Final speed, v = 4 m/s
Time, t = 4 s
We need to find the distance traveled by a bike. Let it is equal to d. Using second equation of kinematics as follows :
[tex]d=ut+\dfrac{1}{2}at^2\\\\\text{a=acceleration of bike and u = 0}\\\\d=\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\d=\dfrac{(v-u)t}{2}\\\\d=\dfrac{(4-0)4}{2}\\\\d=8\ m[/tex]
So, the car cover a distance of 8 m.
The bike will travel the distance of 8 m during the given time interval.
Given data:
The initial speed of bike is, u = 0.0 m/s.
The final speed of bike is, v = 4.0 m/s.
The time interval is, t = 4 s.
In given problem, we need to obtain the magnitude of acceleration first. Then we can use this value in the third kinematic equation of motion, to find the distance covered by bike.
Then by first kinematic equation of motion,
v = u + at
Solving as,
4.0 = 0 + a(4)
a = 1 m/s²
Now, we can use the third kinematic equation of motion to find the distance travelled as,
[tex]v^{2}=u^{2}+2as[/tex]
Solving as,
[tex]4.0^{2}=0^{2}+2(1)s\\\\16 = 2s\\\\s = 8\;\rm m[/tex]
Thus, we can conclude that the bike will travel the distance of 8 m during the given time interval.
Learn more about the kinematic equation of motion here:
https://brainly.com/question/13202575
