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Points P, Q, R, and S are collinear. Point Q is between P and R, R is between Q and S, and PQ =RS. If PS = 21 and PR = 16, what is the value of QR? QR = (Simplify your answer.)​

Respuesta :

tomson1975

Greetings from Brasil...

→ Collinear points = points belonging to the same line

→ PQ is said to be equal to RS. Let’s call this distance X

→ let's call QR Y

With this information and the figure in the annex we can conclude that:

refer to attached

PQ = X

QR = Y

RS = PQ = X

then

PR = PQ + QR

16 = X + Y       i

PS = PR + RS

21 = 16 + X

X = 5       putting in i

16 = X + Y

16 = 5 + Y

Y = 11

So,

PQ = 5

QR = 11

RS = 5

Ver imagen tomson1975
MrRoyal

Collinear points are points on the same line.

The value of QR is 11

From the question, we have:'

  • Q between P and R
  • R between Q and S

This means that:

[tex]\mathbf{PR = PQ + QR}[/tex]

[tex]\mathbf{QS = QR + RS}[/tex]

[tex]\mathbf{PS = PR + RS}[/tex]

The given parameters are:

[tex]\mathbf{PS = 21}[/tex]

[tex]\mathbf{PR = 16}[/tex]

[tex]\mathbf{PQ = RS}[/tex]

Substitute the above values in [tex]\mathbf{PS = PR + RS}[/tex]

[tex]\mathbf{21= 16 + RS}[/tex]

Solve for RS

[tex]\mathbf{RS = 21- 16}[/tex]

[tex]\mathbf{RS = 5}[/tex]

This means that:

[tex]\mathbf{PQ = RS = 5}[/tex]

Substitute 5 for PQ in [tex]\mathbf{PR = PQ + QR}[/tex]

[tex]\mathbf{PR = 5+ QR}[/tex]

Substitute [tex]\mathbf{PR = 16}[/tex] in [tex]\mathbf{PR = 5+ QR}[/tex]

[tex]\mathbf{16 = 5+ QR}[/tex]

Solve for QR

[tex]\mathbf{QR = 16 - 5 }[/tex]

[tex]\mathbf{QR = 11}[/tex]

Hence, the value of QR is 11

Read more about collinear points at:

https://brainly.com/question/1593959

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