Complete Question
The complete question is shown on the first uploaded image
Answer:
6a
[tex]V(3) = 113.112[/tex]
6b
[tex]V(\frac{3}{2}) = 14.139 [/tex]
6c
[tex]V(2r) = 33.514r^3[/tex]
7a
[tex] h(5) = 0 [/tex]
7b
[tex] h(t) = -5.76 [/tex]
7c
[tex] h(x+5) = x(x+5)[/tex]
Step-by-step explanation:
Considering the question 6
The function given is [tex]V(r) = \frac{4}{3} \pi r^3[/tex]
For V(3) we have
[tex]V(3) = \frac{4}{3} \pi 3^3[/tex]
[tex]V(3) = \frac{4}{3} * 3.142 * 3^3[/tex]
[tex]V(3) = 113.112[/tex]
For [tex]V(\frac{3}{2})[/tex]
[tex]V(\frac{3}{2}) = \frac{4}{3} * \pi * (\frac{3}{2})^3 [/tex]
[tex]V(\frac{3}{2}) = \frac{4}{3} * 3.142 * (\frac{3}{2})^3 [/tex]
[tex]V(\frac{3}{2}) = 14.139 [/tex]
For V(2r)
[tex]V(2r) = \frac{4}{3} \pi (2r)^3[/tex]
[tex]V(2r) = \frac{4}{3} * 3.142*8r^3[/tex]
[tex]V(2r) = 33.514r^3[/tex]
Considering the question 7
The function given is [tex] h(t) = t^2 - 5t [/tex]
For h(5)
[tex] h(5) = 5^2 - 5(5) [/tex]
[tex] h(5) = 0 [/tex]
For h(1.8)
[tex] h(t) = 1.8^2 - 5(1.8) [/tex]
[tex] h(t) = -5.76 [/tex]
For h(x+ 5)
[tex] h(x+5) = (x+5)^2 - 5(x+5) [/tex]
[tex] h(x+5) = x^2 + 25+10x-5x-25[/tex]
[tex] h(x+5) = x(x+5)[/tex]
