1. A student says that the zeros of y = (x - 2)(x + 7) are -2 and 7. Is the student correct? If not, describe and correct the error the student made.

2. Explain why x^2 + 25 is not equal to (x + 5)^2?

3. Describe how the factoring can help you find the x-intercepts of the graph of the quadratic function y = x^2 - 4x + 3.

3) The Intercept form of a quadratic equation is: y = a(x - p)(x - q) where p and q are the x-intercepts. Notice that the intercept form IS the factored form. Set the factors equal to zero to find the x-intercepts.

y = x² - 4x + 3

y = (x - 1)(x - 3) --> Intercept form

0 = (x - 1)(x - 3) --> finding the zeros (aka x-intercepts)

0 = x - 1 0 = x - 3

x = 1 x = 3 --> zeros are 1 and 3

yoodyannapolis yoodyannapolis · Answer 2 · 2021-10-21T12:25:17+02:00

1.The zeroes are 2,-7

2.[tex]x^2 + 25\neq ( x + 5)^{2}[/tex]

3. So, factoring can help to find the x-intercepts

1.We have y = (x - 2)(x + 7)

For zeroes of y , Put y=0

(x - 2)(x + 7) =0

x=2,-7

So, the zeroes of y = (x - 2)(x + 7) are 2 and -7.

2. We have [tex]x^2 + 25[/tex]

[tex]x^2 + 25= x^2 + 5^{2}[/tex]

And

[tex](x+ 5)^{2} \\=x^{2} +5^{2} +10x\\=x^{2} +25 +10x\\\neq x^{2} +25[/tex]

So, [tex]x^2 + 25\neq ( x + 5)^{2}[/tex]

3.We have the quadratic function [tex]y = x^2 - 4x + 3[/tex]

[tex]y=x^2 - 4x + 3\\=(x-3)(x-1)\\[/tex]

For x-intercept put y=0, we get

[tex](x-3)(x-1)=0\\x=3,x=1[/tex]

So, factoring can help to find the x-intercepts of the graph of the quadratic function [tex]y = x^2 - 4x + 3.[/tex]

Learn more:https://brainly.com/question/24800104