Answer:
0.469 mol FeCl₃
Explanation:
Your reaction as a chemical equation is:
2 Fe (s) + 3 Cl₂ (g) ⇒ 2 FeCl₃ (s)
You have 26.2 grams of iron. Convert to moles of iron.
(26.2 g)/(55.845 g/mol) = 0.4692 mol
Use the mole ratio from the chemical equation to convert moles of iron to moles of iron(III) chloride.
(0.4692 mol Fe) × (2 mol FeCl₃/2 mol Fe) = 0.469 mol FeCl₃
You will have 0.469 moles of iron(III) chloride at the end of the reaction.
