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Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is selected. Find the probability of selecting a six and then selecting a nine.
The probability of selecting a six and then selecting a nine is
(Round to three decimal places as needed.)

Respuesta :

MathPhys

Answer:

0.006

Step-by-step explanation:

The probability that the first card is a six is 4/52.

There's one less card now, so the probability that the second card is nine is 4/51.

The total probability is:

P = (4/52) (4/51)

P ≈ 0.006

abiolataiwo2015

If Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is selected. Find the probability of selecting a six and then selecting a nine.  The probability of selecting a six and then selecting a nine is 0.006

Let the probability that the first card is six be 4/52

Let the probability that the second card is nine be 4/51

Now let determine the probability of selecting a six and then selecting a nine

Probability (P)=(4/52×4/51)

Probability (P)=16÷2,652

Probability (P)= 0.006

Inconclusion if Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is selected. Find the probability of selecting a six and then selecting a nine.  The probability of selecting a six and then selecting a nine is 0.006

Learn more here:

https://brainly.com/question/18141369

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