Answer:
[tex]a=4.93\times 10^{14}\ m/s^2[/tex]
Step-by-step explanation:
In this question,
Force on the electron is [tex]4.5\times 10^{-16}\ N[/tex]
Mass of the electron is [tex]9.11\times 10^{-31}\ kg[/tex]
Net force, F = ma
So,
[tex]a=\dfrac{F}{m}\\\\4.5\times 10^{-16}\ N=9.11\times 10^{-31}\ kg\times a\\\\a=\dfrac{4.5\times 10^{-16}}{9.11\times 10^{-31}}\\\\a=4.93\times 10^{14}\ m/s^2[/tex]
So, the acceleration of the electron is [tex]4.93\times 10^{14}\ m/s^2[/tex].
