Explanation:
Given that,
Manganese-56 decays by beta emission and has a half-life of 2.6 hours.
We need to find no of half lives in 24 hours. It can be calculated by dividing 24 hours by 2.6 hours. So,
[tex]T=\dfrac{24}{2.6}=9.23\ \text{half lives}[/tex]
Let x mg of a2 0 mg sample remain after 5 half-lives.
[tex]x=20\ mg\times \dfrac{1}{2^5}\\\\x=0.625\ \text{mg}[/tex]
Hence, there are 9.23 half lives and 0.625 mg of sample will remain after 5 half lives.
