Answer:
The coefficient of kinetic friction μ = 0.278
Explanation:
The frictional force on the crate is given by F = μN where μ = the coefficient of kinetic friction and N = normal force. The normal force equals the weight of the crate W = 180 N.
Since the kinetic friction F = 50 N, and the normal force which is the weight of the crate equals N = W = 180 N, the coefficient of kinetic friction μ is given by μ = F/N
= 50 N/180 N
= 0.278
So, the coefficient of kinetic friction μ = 0.278
