Explanation:
Using equations of motion :
(A) we know that,
u = 0
a = 3.7 m/s^2
S = 63
[tex] {v}^{2} = {u}^{2} + 2as[/tex]
[tex]v = \sqrt{0 + 2 \times 3.7 \times 63} = 21.6 \: m{s}^{ - 1} [/tex]
(B)
v = u + at
21.6 = 0 + 3.7 * t
t (time to reach 63 m) = 5.83 seconds
