The Rydberg equation includes the math function with frequency proportional to 1/n2. If
n is changed from 1 to 4, what happens to the frequency.

Respuesta :

Answer:

The frequency decreases 16-fold

Explanation:

In the Rydberg equation, the frequency is proportional to 1/n², so if n is changed from 1 to 4, the frequency will be one-sixteenth of the initial frequency.  

In the Rydberg equation, the frequency is proportional to 1/n²:

[tex]\nu \propto \frac{1}{n^{2}}[/tex]

When n = 1, we have:

[tex]\nu_{i} \propto \frac{1}{n^{2}} \propto \frac{1}{1^{2}}[/tex]  

Now, when n = 4, the frequency is:

[tex]\nu_{f} \propto \frac{1}{4^{2}} \propto \frac{1}{(4*1)^{2}} \propto \frac{1}{4^{2}}*\frac{1}{1^{2}} \propto \frac{\nu_{i}}{16}[/tex]

Therefore, if n is changed from 1 to 4, the frequency will be one-sixteenth of the initial frequency.  

You can learn more about the Rydberg equation here: https://brainly.com/question/5587611?referrer=searchResults

I hope it helps you!

                       

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