Respuesta :
In the Rydberg equation, the frequency is proportional to 1/n², so if n is changed from 1 to 4, the frequency will be one-sixteenth of the initial frequency.
In the Rydberg equation, the frequency is proportional to 1/n²:
[tex]\nu \propto \frac{1}{n^{2}}[/tex]
When n = 1, we have:
[tex]\nu_{i} \propto \frac{1}{n^{2}} \propto \frac{1}{1^{2}}[/tex]
Now, when n = 4, the frequency is:
[tex]\nu_{f} \propto \frac{1}{4^{2}} \propto \frac{1}{(4*1)^{2}} \propto \frac{1}{4^{2}}*\frac{1}{1^{2}} \propto \frac{\nu_{i}}{16}[/tex]
Therefore, if n is changed from 1 to 4, the frequency will be one-sixteenth of the initial frequency.
You can learn more about the Rydberg equation here: https://brainly.com/question/5587611?referrer=searchResults
I hope it helps you!
