Answer:
The horizontal component of the force, [tex]F_x= 34.24 \ N[/tex]
The vertical component of the force, [tex]F_y=7.28 \ N[/tex]
Explanation:
Given;
Force on the rope, F = 35 N
angle between the rope and the horizontal = 12 °
The horizontal component of the force is given by;
[tex]F_x = Fcos \theta\\\\F_x = 35cos(12^0)\\\\F_x = 34.24 \ N[/tex]
The vertical component of the force is given by;
[tex]F_y = Fsin\theta\\\\F_y = 35sin(12^0)\\\\F_y = 7.28 \ N[/tex]
