Answer:
The acceleration is 6 [tex]\frac{m}{s^2}[/tex]
Explanation:
Use Newton's second law to solve the problem:
[tex]Force = mass\,\,*\,\,acceleration\\3\,N = 0.5\,\,kg\,*\,a\\a = \frac{3}{0.5} \frac{m}{s^2} \\a=6\,\,\frac{m}{s^2}[/tex]
the acceleration of the cart given its mass and force exerted is 6m/s².
Given the data in the question;
Mass of lab cart; [tex]m = 0.5kg[/tex]
Force applied; [tex]F = 3N[/tex]
Acceleration of cart; [tex]a = \ ?[/tex]
To determine the acceleration of the cart, we use the expression from Newton's second law of Motion:
[tex]F = m* a[/tex]
Where F is force exerted, m is mass and a is acceleration
We substitute our given values into the equation
[tex]3N = 0.5kg \ * \ a\\\\3kgm/s^2 = 0.5kg\ *\ a\\\\a = \frac{3kgm/s^2}{0.5kg} \\\\a = 6m/s^2[/tex]
Therefore, the acceleration of the cart given its mass and force exerted is 6m/s².
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