Step-by-step explanation:
Hey there!
Here;
A chord of a circle AB is given with measure of 24 cm.
Let O be the centre of a circle and OP is perpendicular to AB.
Now, draw an imaginary line from O to B. [To make a radius].
Now;
[tex]bp = \frac{1}{2} \times ab[/tex]
[tex]bp = \frac{1}{2 } \times 24[/tex]
Therefore BP = 12.
Again;
You can clearly see that POB is a Right angled triangle.
Now,
Using Pythagoras relation we get;
[tex] {ob} = \sqrt{ {po}^{2} + {bp}^{2} } [/tex]
[tex]ob = \sqrt{ {8}^{2} + {12}^{2} } [/tex]
[tex]ob = \sqrt{64 + 144} [/tex]
[tex]ob = \sqrt{208} [/tex]
Therefore OB = 14.42.
As OB is a radius, the value of radius is 14.42.
Hope it helps...
