The velocity gained by the car is the same, over the given periods
therefore, the work required to change the velocity would be the same.
The true statements are;
- The change in energy for both process is the same
- Both process take the same amount of energy
Reasons:
The amount of work done from in accelerating from 0 to 60 mph is given
by the kinetic energy gained (the change in kinetic energy)
[tex]\mathrm{Change \ in \ kinetic \ energy, \Delta K.E.} = \dfrac{1}{2} \cdot m \cdot v_f^2 - \dfrac{1}{2} \cdot m \cdot v_i^2[/tex]
Where;
m = Mass
[tex]v_i[/tex] = The initial velocity
[tex]v_f[/tex] = The final velocity
Which gives;
Work done by, W, accelerating in 10 seconds, is given as follows;
[tex]\Delta K.E. = W_{10 \, seconds} = \dfrac{1}{2} \cdot m \times 60^2 - \dfrac{1}{2} \cdot m \times 60^2 = 1800 \cdot m[/tex] -
Work done by, W, accelerating in 30 seconds, is given as follows;
[tex]\Delta K.E. = W_{30 \, seconds} = \dfrac{1}{2} \cdot m \times 60^2 - \dfrac{1}{2} \cdot m \times 60^2 = 1800 \cdot m[/tex] -
Therefore;
- The change in energy for both process is the same
- Both process take the same amount of energy
Learn more here:
https://brainly.com/question/15598542
