a heat engine produces 8200 j of heat while performing 3200 of useful work. what is the efficiency of this engine? (i'm doing something wrong.)

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MonsieurPengu MonsieurPengu · Answer 1 · 2016-09-21T22:12:40+02:00

So E u(seful) is 3200 J and E l(oss) is 8200 J. E t(otal) is thus 11400 J. For the efficiency you do E u/ E t so 3200/11 400= 0.28 or 28%

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aksnkj aksnkj · Answer 2 · 2021-12-09T13:43:25+01:00

The efficiency of this engine is 28.07%.

Given information:

The heat produced (loss) by the engine is [tex]h_l=8200[/tex] J.

The useful work (work done) by the engine is [tex]W=3200[/tex] J.

By the conservation of energy, the total energy supplied by the engine will be,

[tex]H=h_l+W\\H=8200+3200\\H=11400\rm\; J[/tex]

Now, efficiency is the ratio of useful work and the total energy supplied by the engine.

So, the efficiency can be calculated as,

[tex]\eta=\dfrac{W}{H}\\\eta=\dfrac{3200}{11400}\\\eta=0.2807=28.07\%[/tex]

Therefore, the efficiency of this engine is 28.07%.

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