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the slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. what is the point-slope form of the equation for this line? y – 13 = 5(x – 2) y 13 = 5(x 2) y – 2 = 5(x – 13) y 2 = 5(x 13

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nobillionaireNobley
Slope intercept form of equation of a line is given by y = mx + c where m is the slope
Point slope form is given by y - y1 = m(x - x1); where (x1, y1) is any point on the line.
Required equation is y - (-13) = 5(x - (-2))
y + 13 = 5(x + 2)
DingDongHong

Answer:

y + 13 = 5(x + 2)

Step-by-step explanation:

Point-slope form is y - y1 = m(x - x1)

Point is (-2,-13)

Plug in the numbers

y - [-13] = 5( x - [-2] )

Simplify

y + 13 = 5(x + 2)

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