Respuesta :
You would use
d = v0*t + 0.5at^2
Solve for t. v0 is 0, d is 18 and a is -9.81
t = sqrt(18/4.9)
d = v0*t + 0.5at^2
Solve for t. v0 is 0, d is 18 and a is -9.81
t = sqrt(18/4.9)
The distance fallen through gravity in ' t ' seconds is
Distance = (1/2) (acceleration of gravity) (t²)
18 meters = (1/2) · (9.8 m/s²) · (t²)
Divide each side by (4.9 m/s²):
(18 m) / (4.9 m/s²) = t²
3.67 sec² = t²
Square root each side: 1.92 sec = t . (rounded)
That's not much time. But Peter Pan never got old, so
presumably he hasn't got too much life to flash through.
He may be OK with 1.92 seconds. Maybe even enough
time to linger momentarily over some of the juicier parts.
Distance = (1/2) (acceleration of gravity) (t²)
18 meters = (1/2) · (9.8 m/s²) · (t²)
Divide each side by (4.9 m/s²):
(18 m) / (4.9 m/s²) = t²
3.67 sec² = t²
Square root each side: 1.92 sec = t . (rounded)
That's not much time. But Peter Pan never got old, so
presumably he hasn't got too much life to flash through.
He may be OK with 1.92 seconds. Maybe even enough
time to linger momentarily over some of the juicier parts.