Respuesta :

mean = (1/n)∑(i=1 to n)xi 

= (1/6){92 + 97 + 53 + 90 + 95 + 98} 
= 87.5 

variance = [(1/n)*∑(i=1 to n)(xi-m)^2] m denotes mean


= (1/6){(92-87.5)^2 + (97-87.5)^2 + (53-87.5)^2 + (90-87.5)^2 + (95-87.5)^2 + (98-87.5)^2} 
= 245.6 

standard deviation = √[1/(n-1)*∑(i=1 to n)(x-x)^2]

= √{1/6*[(92-87.5)^2 + (97-87.5)^2 + (53-87.5)^2 + (90-87.5)^2 + (95-87.5)^2 + (98-87.5)^2]} 
= 15.7 

so we got 
mean = 87.5 
variance = 245.6 
standard deviation = 15.7 
hope this helps

Answer: Hihiiiii, for future visitors the answers to the rest of the quick check are..

1: B: mean=87.5 variance=245.6 standard deviation=15.7

2: A: mean=47.6 variance=31 standard deviation=5.6

3: D: 2

4: B: 2

Hope this helpsss!! If anyone could give brainliest that'd be cool even though im late lol :p

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