Respuesta :

[NH4]+ + [Cl]- + [Na]+ + [OH]- -----> H20 (l) + HN3(g) + [Na]+ + [Cl]- this is ionic equation
 [Na]+ and [Cl]- can be subtracted from both sides. 
NET ionic equation
=[NH4]+ + [OH]- -----> H20 (l) + HN3(g) 
 net ionic equations  represents solids, liquids, or gasses are formed and what ions form them
hope it helps

Answer : The net ionic equation will be,

[tex]NH_4^+(aq)+OH^{-}(aq)\rightarrow H_2O(l)+NH_3(g)[/tex]

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

[tex]NH_4Cl(aq)+NaOH(aq)\rightarrow H_2O(l)+NH_3(g)+NaCl(aq)[/tex]

The ionic equation in separated aqueous solution will be,

[tex]NH_4^+(aq)+Cl^{-}(aq)+Na^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)+NH_3(g)+Na^+(aq)+Cl^{-}(aq)[/tex]

In this equation, [tex]Na^+\text{ and }Cl^-[/tex] are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

[tex]NH_4^+(aq)+OH^{-}(aq)\rightarrow H_2O(l)+NH_3(g)[/tex]